eachLeft
Syntax
eachLeft(func, X, Y, [consistent=false])
or
X <operator>:L Y
(when consistent = false)
or
X <operator>:LC Y
(when consistent = true)
or
func:L(X, Y)
(when consistent = false)
or
func:LC(X, Y)
(when consistent = true)
Arguments
func is a binary function.
X/ Y is a vector/matrix/table/array vector/dictionary.
consistent is a Boolean value. The default value is false, indicating that the data type of the result is determined by each calculation result. Otherwise, the data type of the result is the same as the data type of the first calculation result. Note that if the data forms of result are inconsistent, consistent can only be specified as false. Otherwise, an error will be reported.
Details
Calculate func(X(i),Y)
for each element of X.

X(i)
is each element when X is a vector. 
X(i)
is each column when X is a matrix. 
X(i)
is each row when X is a table. 
X(i)
is each row when X is an array vector. 
X(i)
is each value when X is a dictionary.
If func supports vector operation and the input is a vector, we should use the
vector function/operator directly instead of the eachLeft
template
for better performance.
Examples
eachLeft
with 2 vectors:
x = 4 3 2 1
y = 3 0 6;
x +:L y;
4  3  2  1 

7  6  5  4 
4  3  2  1 
10  9  8  7 
eachLeft(pow, x, y);
4  3  2  1 

64  27  8  1 
1  1  1  1 
4096  729  64  1 
eachLeft
with a vector and a matrix:
x=1..6$2:3;
x;
col1  col2  col3 

1  3  5 
2  4  6 
x ** :L 1 1;
// output
[3,7,11]
eachLeft
with 2 matrices:
y=6..1$2:3;
y;
col1  col2  col3 

6  4  2 
5  3  1 
z = x **:L y;
z;
// output
(#0 #1 #2
  
16 10 4
,#0 #1 #2
  
38 24 10
,#0 #1 #2
  
60 38 16
)
typestr z;
ANY VECTOR
eachLeft
with a dictionary and a vector:
d=dict(`a`b`c, [[1, 2, 3],[4, 5, 6], [7, 8, 9]])
eachLeft(add,d,10 20 30)
// output
a>[11,22,33]
b>[14,25,36]
c>[17,28,39]